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Molding cavity size of the formula calculating the correction factor

To: When the workpiece material shrinkage than the average shrinkage rate is high, the parts than the actual size of the average shrinkage rate at the time small (k a k almost), so in this case should satisfy the inequality; a-xa ≥ (k large almost a k),[link widoczny dla zalogowanych], after finishing the above two inequalities, have a + ≤ Zn ≤ l .... ⑥ 6U core formula d = (L4-Lk flat 4-xa) a 6. x factor to the Formula the same as above,[link widoczny dla zalogowanych], from precisely the same formula with the formula ⑥. Fourth, a few examples 1. ⑥ trial to determine the instance of the formula, when the axis, bso_o. . 2, material shrinkage was 0,[link widoczny dla zalogowanych],002 ~ 0.010,6 time =} = 0.124, x for the range. 0 solutions: the l = 50,[link widoczny dla zalogowanych], k = 0.010, k = 0.002, a = 0.62, n = 5 into the formula @,[link widoczny dla zalogowanych], was: 0.523 <~ x ≤ 0.677 and thus we can see, the above examples The reason why parts may sometimes tolerance, not because of x = 0.75 0.523 <~ x ≤ O. 677 between the reason. So x value should be between 0.523 ≤ x ≤ 0.677 selected. 2. Size of the known parts were 50H1l (B .), material shrinkage was 0.002 ~ 0.010, n = 5, try to determine the range of x. tooling industry 19891No.3 total solutions to problems in the conditions of 9735, respectively, into the formula ⑥, was when the workpiece size is ~ 50Hll , 1.45 ≤ x ≤ 0.25 ... ... ⑦ parts of a size of ~ 50H12 time, 1 ≤ x ≤ O.2 ... ... ⑧ When the workpiece size is $ 50H13, 0.713 ≤ x ≤ O.487 ... ... ⑤ When the workpiece size is ~ 50H14, 0.523 ≤ x ≤ 0.677 ... ... ⑩ workpiece size is ~, 5oH15 time, o.4 ≤ x ≤ 0.8 ... ... @ workpiece size OHl6 when 0.325 ≤ x ≤ 0.875 ... ... ⑨ the inequality ⑦, ⑧ ③ does not hold, can be seen in the shrinkage rate of 0.002 ~ 0.010, n = 5, hole accuracy is higher than l4-class parts, you can not calculated by the formula ③ shape size, that is, the production cavity mold parts - generally can not achieve this precision. From the inequality ⑩, @, @ x is not limited to general information see the provisions of the x coefficient of Ni in 1 / 2 to 3 / 4, between The greater range of choice is more important, because clearly the range of x, can be based on the different parts requirements, select the correct value of x, and the extrusion die technology of rubber mold rubber diaphragm curing mold design Jn Precision machinery plant in Liaoning Tieling Xiarong Wu rubber diaphragm (Figure 1) is widely used in gas, natural gas and other flammable gases in the chemical gas pipeline valve, flow meter seals on the Figure 1. This patch requires smooth surface, uniform thickness of special requests. vulcanization mold this patch, the use of general rubber vulcanization, as is usually the metal mold is no guarantee that the diaphragm of uniform thickness (usually 5 = 0.2 ± 0.03) in the. We designed the diaphragm curing mold shown in Figure 2: 1 piece in the mold, the mold parts 2, 3 pieces of plastic products for the core pieces 4 pieces 6 for the next module, of which 6 cases according to the cavity area and considering the size of the diaphragm membrane shrinkage computed, as shown in Figure 2, sodium sulfide in the size of a model is calculated as: a = a (1 ten k)-style plans for the product in a size of k is in the rubber diaphragm ( not rubber) shrinkage cavity roughness is not greater than R. = 0.8 at C in Figure 2 (peripheral) parts 1 and 5 unilateral cases are 0.4 ~ O.5 to ensure the uniformity of the gap . Annex 4 dirty core dump has been processed the user dies, the use of high hardness (Shore 70 ~ 80 Figure 2 degrees) of the self-curing rubber, and curing time can be much more use. we use the natural contraction and rubber core flexibility to ensure their smooth surface and the thickness of the diaphragm uniform. mold material for the 45 quenched and tempered steel, hard chrome plated. With the former technology, changing the shape of the diaphragm, seven is also growing a certain unit from abroad; l products into such a rubber diaphragm in education, as shown in Figure 3. printed on ordinary diaphragm in a circle around the oak was added Jiao skeleton, model how to cure this' alt account nickname? If you are still using the above approach, but on the next mold cavity to pre-processing of the skeleton, so that the products cure, due to the contraction of the diaphragm compound with different rates, the lance will form around the glass off so we are resolved first by the diaphragm The shrinkage rate of the cavity size of ministries, basically the same as in Figure 2 (see Figure 4C). and then compound designed specifically curing shrinkage of the mold frame 36 of the total 97 industrial 1989.No.8

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